HOW DO I EVEN APPROACH THIS....
QUICK
Started by kittycat, Oct 30 2011 03:42 PM
10 replies to this topic
#1
Posted 30 October 2011 - 03:42 PM
HOW DO I EVEN APPROACH THIS....
#2
Posted 30 October 2011 - 03:47 PM
Covered Area = 80 - 8x - 10(8-x) - x(10-x). I really have no clue. All I did was just find the areas of the uncovered triangle. Once you multiple things through the equation will look like a quadratic.
After taking Applied Math II, geometry and algebra became really hard
After taking Applied Math II, geometry and algebra became really hard
Edited by Keil, 30 October 2011 - 04:24 PM.
#3
Posted 30 October 2011 - 03:48 PM
You need to find the vertex and all you're given are the points (0,0), (?,8) and (10,?)
#4
Posted 30 October 2011 - 03:48 PM
Psh, who would have a triangular rug
#5
Posted 30 October 2011 - 03:49 PM
Oh wait, yeah that makes sense I can do this! Just never thought of doing that lmao, thank you.
#6
Posted 30 October 2011 - 03:58 PM
Psh, who would have a triangular rug
Lol! CX
&I was going to help.. but it seems like you've got it now? o:
#7
Posted 30 October 2011 - 04:55 PM
Fixed my mistakes but still confused with the original question
I'm getting 88 as my answer...
I'm getting 88 as my answer...
Edited by kittycat, 30 October 2011 - 05:57 PM.
#8
Posted 30 October 2011 - 08:50 PM
The total area would be 10x8 which is 80m2
You have three different uncovered triangles, so you find the areas of each. Base*Height/2
1) (8 by x)/2 = 4x
2) (x by (10-x))/2 = .5(10x-x^2)
3) (10 by (8-x))/2 = 40-5x
So the quadratic formula for uncovered area would be
= (4x + 5x - ((x^2)/2) + 40 - 5x)
= (4x - ((x^2)/2) + 40)
= (4x - .5x + 40)
= 3.5x + 40
You would then set that to equal 0 to find the maximum x value, and thus the maximum uncovered area of the floor
My math in terms of quadratic equations is extremely rusty, so there's a very very good chance this is wrong, but it might give you the right idea to put you on the right track.. if not just ignore it sorry I couldn't be more help, I haven't taken math in a while
Edit: Something is wrong.. not sure what and too tired to try to figure it out right now, I'll check again in the morning.. maybe my brain will start working again
You have three different uncovered triangles, so you find the areas of each. Base*Height/2
1) (8 by x)/2 = 4x
2) (x by (10-x))/2 = .5(10x-x^2)
3) (10 by (8-x))/2 = 40-5x
So the quadratic formula for uncovered area would be
= (4x + 5x - ((x^2)/2) + 40 - 5x)
= (4x - ((x^2)/2) + 40)
= (4x - .5x + 40)
= 3.5x + 40
You would then set that to equal 0 to find the maximum x value, and thus the maximum uncovered area of the floor
My math in terms of quadratic equations is extremely rusty, so there's a very very good chance this is wrong, but it might give you the right idea to put you on the right track.. if not just ignore it sorry I couldn't be more help, I haven't taken math in a while
Edit: Something is wrong.. not sure what and too tired to try to figure it out right now, I'll check again in the morning.. maybe my brain will start working again
#9
Posted 30 October 2011 - 09:39 PM
Thanks Jakerz. I love topics like these.
#10
Posted 31 October 2011 - 04:45 AM
You have 3 uncovered parts:
Triangle 1 Area = 0.5*8*x
Triangle 2 Area = 0.5*(10-x)*x
Triangle 3 Area = 0.5*10*(8-x)
Total Uncovered Area = Triangle 1 Area + Triangle 2 Area + Triangle 3 Area
= 0.5*8*x + 0.5*(10-x)*x + 0.5*10*(8-x)
= 40 + 4*x - 0.5*x^2
The question asks for the maximum uncovered area, so you can plot the graph or differentiate and solve for dA/dt = 0 then sub into the uncovered area equation.
Either way, the total uncovered area is at a max when x = 4
Triangle 1 Area = 0.5*8*x
Triangle 2 Area = 0.5*(10-x)*x
Triangle 3 Area = 0.5*10*(8-x)
Total Uncovered Area = Triangle 1 Area + Triangle 2 Area + Triangle 3 Area
= 0.5*8*x + 0.5*(10-x)*x + 0.5*10*(8-x)
= 40 + 4*x - 0.5*x^2
The question asks for the maximum uncovered area, so you can plot the graph or differentiate and solve for dA/dt = 0 then sub into the uncovered area equation.
Either way, the total uncovered area is at a max when x = 4
Edited by iomega, 31 October 2011 - 04:47 AM.
#11
Posted 31 October 2011 - 02:44 PM
Thanks to all, it's great that you didn't give me the final answer I like that.
Anyway the answer is 48m^2 to anyone curious. Thanks for all the help
Anyway the answer is 48m^2 to anyone curious. Thanks for all the help
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