Um, I just woke up so what you're writing is confusing me. I'm just going to ignore all of it and try to explain it...using paint!

That's an NO
2- right? Basically, it has N x1 = 5e-, O x2 = 12e-, and 1 e- to balance the charges which makes it an anion. First, draw the diagram and distribute the charges appropriately. There are 6 valence e- in the O on the left and it's sharing one bond. According to charge distribution, you count number of valence electrons and half the number of electrons in a bond (the O-N) bond, and that number of subtracted from the total number of valence electrons in the unbonded form of that element (6e- for O). N has 2 valence e- and 3 bonds, so that's a total of 5, minus 5 from that, which gives a charge of 0.
tbc...
Again for NO
3- you count up the numbers and draw the structure. The bottom two O have a negative charge because they each have 6 valence e- and one bond, so that makes a total of 7 for charge. 6-7 = -1, so they both have a charge of -1. The top O has 4 valence e, 2 bonds, so that makes 6e-, subtracted from 6 so that has a neutral charge of zero. the N in the middle has 4 bonded e-, but the total number is supposed to be 5 to be balanced, so 5-4 = +1 so it has a positive one charge.
Edited by Kyuu, 28 October 2009 - 02:48 PM.