7 replies to this topic

[Rambo]

Write a for loop which uses an iteration variable of type double. This should start with a value of 0.5, iterate by steps of 0.3 until the iteration variable exceeds 2. Run the loop, maybe using the CodePad. What is produced? Explain why. Hint: how are floating point ('real') numbers stored?


Help :|

[Dan]

for (double d = 0.5; d < 2; d += 0.3)
{
	//Console.WriteLine(d);  // C#
	System.out.println(d); // Java
}

Is your for loop.

Run it, see what results you get. Refer to Floating Point to figure out why you're getting what values you're getting.

[Waser Lave]

for (double d = 0.5; d < 2; d += 0.3)
{
	//Console.WriteLine(d);  // C#
	System.out.println(d); // Java
}

Is your for loop.

Run it, see what results you get. Refer to Floating Point to figure out why you're getting what values you're getting.

Technically you should probably do <= 2 because they ask for the loop to run until it exceeds 2.

[Dan]

Technically you should probably do <= 2 because they ask for the loop to run until it exceeds 2.

Ah well spotted. Right you are.

[Rambo]

Kinda having trouble explaining this, could anyone help?

[Melchoire]

I ran something very similar in C++:

#include <iostream>

using namespace std;

void main(void)
{
	for(double d=0.5; d <= 2.0; d+=0.3)
	{
		cout << d << endl;
	}
}

the out put is:
0.5
0.8
1.1
1.4
1.7
2


What's to explain about it?

[Rambo]

It goes up in .3

[Melchoire]

I don't get the point of that hint that they give you.